/*- * SPDX-License-Identifier: BSD-2-Clause * * Copyright (c) 2001 Alexey Zelkin * All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in the * documentation and/or other materials provided with the distribution. * * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF * SUCH DAMAGE. */ #include #include #include #include static const char nogrouping[] = { '\0' }; /* * Internal helper used to convert grouping sequences from string * representation into POSIX specified form, i.e. * * "3;3;-1" -> "\003\003\177\000" */ const char * __fix_locale_grouping_str(const char *str) { char *src, *dst; char n; if (str == NULL || *str == '\0') { return nogrouping; } for (src = (char*)str, dst = (char*)str; *src != '\0'; src++) { /* input string examples: "3;3", "3;2;-1" */ if (*src == ';') continue; if (*src == '-' && *(src+1) == '1') { *dst++ = CHAR_MAX; src++; continue; } if (!isdigit((unsigned char)*src)) { /* broken grouping string */ return nogrouping; } /* assume all numbers <= 99 */ n = *src - '0'; if (isdigit((unsigned char)*(src+1))) { src++; n *= 10; n += *src - '0'; } *dst = n; /* NOTE: assume all input started with "0" as 'no grouping' */ if (*dst == '\0') return (dst == (char*)str) ? nogrouping : str; dst++; } *dst = '\0'; return str; }