/*- * Copyright (c) 1991, 1993 * The Regents of the University of California. All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in the * documentation and/or other materials provided with the distribution. * 3. Neither the name of the University nor the names of its contributors * may be used to endorse or promote products derived from this software * without specific prior written permission. * * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF * SUCH DAMAGE. */ #ifndef lint static const char sccsid[] = "@(#)kerberos.c 8.3 (Berkeley) 5/30/95"; #endif /* not lint */ /* * Copyright (C) 1990 by the Massachusetts Institute of Technology * * Export of this software from the United States of America is assumed * to require a specific license from the United States Government. * It is the responsibility of any person or organization contemplating * export to obtain such a license before exporting. * * WITHIN THAT CONSTRAINT, permission to use, copy, modify, and * distribute this software and its documentation for any purpose and * without fee is hereby granted, provided that the above copyright * notice appear in all copies and that both that copyright notice and * this permission notice appear in supporting documentation, and that * the name of M.I.T. not be used in advertising or publicity pertaining * to distribution of the software without specific, written prior * permission. M.I.T. makes no representations about the suitability of * this software for any purpose. It is provided "as is" without express * or implied warranty. */ #ifdef KRB4 #include #include #include /* BSD wont include this in krb.h, so we do it here */ #include #include #include #include #include "encrypt.h" #include "auth.h" #include "misc.h" int kerberos4_cksum(unsigned char *, int); int kuserok(AUTH_DAT *, char *); extern int auth_debug_mode; static unsigned char str_data[1024] = { IAC, SB, TELOPT_AUTHENTICATION, 0, AUTHTYPE_KERBEROS_V4, }; #define KRB_AUTH 0 /* Authentication data follows */ #define KRB_REJECT 1 /* Rejected (reason might follow) */ #define KRB_ACCEPT 2 /* Accepted */ #define KRB_CHALLENGE 3 /* Challenge for mutual auth. */ #define KRB_RESPONSE 4 /* Response for mutual auth. */ static KTEXT_ST auth; static char name[ANAME_SZ]; static AUTH_DAT adat = { 0, "", "", "", 0, {}, 0, 0, 0, { 0, "", 0 } }; #ifdef ENCRYPTION static Block session_key = { 0 }; static DES_key_schedule sched; static Block challenge = { 0 }; #endif /* ENCRYPTION */ static char krb_service_name[] = "rcmd"; static char empty[] = ""; static int Data(Authenticator *ap, int type, const unsigned char *d, int c) { unsigned char *p = str_data + 4; const unsigned char *cd = d; if (c == -1) c = strlen(cd); if (auth_debug_mode) { printf("%s:%d: [%d] (%d)", str_data[3] == TELQUAL_IS ? ">>>IS" : ">>>REPLY", str_data[3], type, c); printd(d, c); printf("\r\n"); } *p++ = ap->type; *p++ = ap->way; *p++ = type; while (c-- > 0) { if ((*p++ = *cd++) == IAC) *p++ = IAC; } *p++ = IAC; *p++ = SE; if (str_data[3] == TELQUAL_IS) printsub('>', &str_data[2], p - (&str_data[2])); return(net_write(str_data, p - str_data)); } int kerberos4_init(Authenticator *ap __unused, int server) { FILE *fp; if (server) { str_data[3] = TELQUAL_REPLY; if ((fp = fopen(KEYFILE, "r")) == NULL) return(0); fclose(fp); } else { str_data[3] = TELQUAL_IS; } return(1); } char dst_realm_buf[REALM_SZ], *dest_realm = NULL; int dst_realm_sz = REALM_SZ; int kerberos4_send(Authenticator *ap) { KTEXT_ST lauth; char instance[INST_SZ]; char *realm; CREDENTIALS cred; int r; printf("[ Trying KERBEROS4 ... ]\n"); if (!UserNameRequested) { if (auth_debug_mode) { printf("Kerberos V4: no user name supplied\r\n"); } return(0); } memset(instance, 0, sizeof(instance)); if ((realm = krb_get_phost(RemoteHostName))) strncpy(instance, realm, sizeof(instance)); instance[sizeof(instance)-1] = '\0'; realm = dest_realm ? dest_realm : krb_realmofhost(RemoteHostName); if (!realm) { printf("Kerberos V4: no realm for %s\r\n", RemoteHostName); return(0); } if ((r = krb_mk_req(&lauth, krb_service_name, instance, realm, 0L))) { printf("mk_req failed: %s\r\n", krb_err_txt[r]); return(0); } if ((r = krb_get_cred(krb_service_name, instance, realm, &cred))) { printf("get_cred failed: %s\r\n", krb_err_txt[r]); return(0); } if (!auth_sendname(UserNameRequested, strlen(UserNameRequested))) { if (auth_debug_mode) printf("Not enough room for user name\r\n"); return(0); } if (auth_debug_mode) printf("Sent %d bytes of authentication data\r\n", lauth.length); if (!Data(ap, KRB_AUTH, (void *)lauth.dat, lauth.length)) { if (auth_debug_mode) printf("Not enough room for authentication data\r\n"); return(0); } #ifdef ENCRYPTION /* * If we are doing mutual authentication, get set up to send * the challenge, and verify it when the response comes back. */ if ((ap->way & AUTH_HOW_MASK) == AUTH_HOW_MUTUAL) { register int i; DES_key_sched(&cred.session, sched); DES_random_key(&session_key); DES_ecb_encrypt(&session_key, &session_key, sched, 0); DES_ecb_encrypt(&session_key, &challenge, sched, 0); /* * Increment the challenge by 1, and encrypt it for * later comparison. */ for (i = 7; i >= 0; --i) { register int x; x = (unsigned int)challenge[i] + 1; challenge[i] = x; /* ignore overflow */ if (x < 256) /* if no overflow, all done */ break; } DES_ecb_encrypt(&challenge, &challenge, sched, 1); } #endif /* ENCRYPTION */ if (auth_debug_mode) { printf("CK: %d:", kerberos4_cksum(lauth.dat, lauth.length)); printd(lauth.dat, lauth.length); printf("\r\n"); printf("Sent Kerberos V4 credentials to server\r\n"); } return(1); } void kerberos4_is(Authenticator *ap, unsigned char *data, int cnt) { #ifdef ENCRYPTION Session_Key skey; Block datablock; #endif /* ENCRYPTION */ char realm[REALM_SZ]; char instance[INST_SZ]; int r; if (cnt-- < 1) return; switch (*data++) { case KRB_AUTH: if (krb_get_lrealm(realm, 1) != KSUCCESS) { Data(ap, KRB_REJECT, "No local V4 Realm.", -1); auth_finished(ap, AUTH_REJECT); if (auth_debug_mode) printf("No local realm\r\n"); return; } memmove((void *)auth.dat, (void *)data, auth.length = cnt); if (auth_debug_mode) { printf("Got %d bytes of authentication data\r\n", cnt); printf("CK: %d:", kerberos4_cksum(auth.dat, auth.length)); printd(auth.dat, auth.length); printf("\r\n"); } instance[0] = '*'; instance[1] = 0; if ((r = krb_rd_req(&auth, krb_service_name, instance, 0, &adat, empty))) { if (auth_debug_mode) printf("Kerberos failed him as %s\r\n", name); Data(ap, KRB_REJECT, krb_err_txt[r], -1); auth_finished(ap, AUTH_REJECT); return; } #ifdef ENCRYPTION memmove((void *)session_key, (void *)adat.session, sizeof(Block)); #endif /* ENCRYPTION */ krb_kntoln(&adat, name); if (UserNameRequested && !kuserok(&adat, UserNameRequested)) Data(ap, KRB_ACCEPT, NULL, 0); else Data(ap, KRB_REJECT, "user is not authorized", -1); auth_finished(ap, AUTH_USER); break; case KRB_CHALLENGE: #ifndef ENCRYPTION Data(ap, KRB_RESPONSE, NULL, 0); #else /* ENCRYPTION */ if (!VALIDKEY(session_key)) { /* * We don't have a valid session key, so just * send back a response with an empty session * key. */ Data(ap, KRB_RESPONSE, NULL, 0); break; } DES_key_sched(&session_key, sched); memmove((void *)datablock, (void *)data, sizeof(Block)); /* * Take the received encrypted challenge, and encrypt * it again to get a unique session_key for the * ENCRYPT option. */ DES_ecb_encrypt(&datablock, &session_key, sched, 1); skey.type = SK_DES; skey.length = 8; skey.data = session_key; encrypt_session_key(&skey, 1); /* * Now decrypt the received encrypted challenge, * increment by one, re-encrypt it and send it back. */ DES_ecb_encrypt(&datablock, &challenge, sched, 0); for (r = 7; r >= 0; r--) { register int t; t = (unsigned int)challenge[r] + 1; challenge[r] = t; /* ignore overflow */ if (t < 256) /* if no overflow, all done */ break; } DES_ecb_encrypt(&challenge, &challenge, sched, 1); Data(ap, KRB_RESPONSE, challenge, sizeof(challenge)); #endif /* ENCRYPTION */ break; default: if (auth_debug_mode) printf("Unknown Kerberos option %d\r\n", data[-1]); Data(ap, KRB_REJECT, NULL, 0); break; } } void kerberos4_reply(Authenticator *ap, unsigned char *data, int cnt) { #ifdef ENCRYPTION Session_Key skey; #endif /* ENCRYPTION */ if (cnt-- < 1) return; switch (*data++) { case KRB_REJECT: if (cnt > 0) { printf("[ Kerberos V4 refuses authentication because %.*s ]\r\n", cnt, data); } else printf("[ Kerberos V4 refuses authentication ]\r\n"); auth_send_retry(); return; case KRB_ACCEPT: printf("[ Kerberos V4 accepts you ]\n"); if ((ap->way & AUTH_HOW_MASK) == AUTH_HOW_MUTUAL) { /* * Send over the encrypted challenge. */ #ifndef ENCRYPTION Data(ap, KRB_CHALLENGE, NULL, 0); #else /* ENCRYPTION */ Data(ap, KRB_CHALLENGE, session_key, sizeof(session_key)); DES_ecb_encrypt(&session_key, &session_key, sched, 1); skey.type = SK_DES; skey.length = 8; skey.data = session_key; encrypt_session_key(&skey, 0); #endif /* ENCRYPTION */ return; } auth_finished(ap, AUTH_USER); return; case KRB_RESPONSE: #ifdef ENCRYPTION /* * Verify that the response to the challenge is correct. */ if ((cnt != sizeof(Block)) || (0 != memcmp((void *)data, (void *)challenge, sizeof(challenge)))) { #endif /* ENCRYPTION */ printf("[ Kerberos V4 challenge failed!!! ]\r\n"); auth_send_retry(); return; #ifdef ENCRYPTION } printf("[ Kerberos V4 challenge successful ]\r\n"); auth_finished(ap, AUTH_USER); #endif /* ENCRYPTION */ break; default: if (auth_debug_mode) printf("Unknown Kerberos option %d\r\n", data[-1]); return; } } int kerberos4_status(Authenticator *ap __unused, char *nam, int level) { if (level < AUTH_USER) return(level); if (UserNameRequested && !kuserok(&adat, UserNameRequested)) { strcpy(nam, UserNameRequested); return(AUTH_VALID); } else return(AUTH_USER); } #define BUMP(buf, len) while (*(buf)) {++(buf), --(len);} #define ADDC(buf, len, c) if ((len) > 0) {*(buf)++ = (c); --(len);} void kerberos4_printsub(unsigned char *data, int cnt, unsigned char *buf, int buflen) { char lbuf[32]; register int i; buf[buflen-1] = '\0'; /* make sure its NULL terminated */ buflen -= 1; switch(data[3]) { case KRB_REJECT: /* Rejected (reason might follow) */ strncpy((char *)buf, " REJECT ", buflen); goto common; case KRB_ACCEPT: /* Accepted (name might follow) */ strncpy((char *)buf, " ACCEPT ", buflen); common: BUMP(buf, buflen); if (cnt <= 4) break; ADDC(buf, buflen, '"'); for (i = 4; i < cnt; i++) ADDC(buf, buflen, data[i]); ADDC(buf, buflen, '"'); ADDC(buf, buflen, '\0'); break; case KRB_AUTH: /* Authentication data follows */ strncpy((char *)buf, " AUTH", buflen); goto common2; case KRB_CHALLENGE: strncpy((char *)buf, " CHALLENGE", buflen); goto common2; case KRB_RESPONSE: strncpy((char *)buf, " RESPONSE", buflen); goto common2; default: sprintf(lbuf, " %d (unknown)", data[3]); strncpy((char *)buf, lbuf, buflen); common2: BUMP(buf, buflen); for (i = 4; i < cnt; i++) { sprintf(lbuf, " %d", data[i]); strncpy((char *)buf, lbuf, buflen); BUMP(buf, buflen); } break; } } int kerberos4_cksum(unsigned char *d, int n) { int ck = 0; /* * A comment is probably needed here for those not * well versed in the "C" language. Yes, this is * supposed to be a "switch" with the body of the * "switch" being a "while" statement. The whole * purpose of the switch is to allow us to jump into * the middle of the while() loop, and then not have * to do any more switch()s. * * Some compilers will spit out a warning message * about the loop not being entered at the top. */ switch (n&03) while (n > 0) { case 0: ck ^= (int)*d++ << 24; --n; case 3: ck ^= (int)*d++ << 16; --n; case 2: ck ^= (int)*d++ << 8; --n; case 1: ck ^= (int)*d++; --n; } return(ck); } #endif